Tuesday, 24 March 2015

Algebra (I): What's Wrong?

18 comments:

  1. It should be plus 10 y at the 2nd line
    Not minus 10 y at the 2nd line

    ReplyDelete
  2. Line 2: should be =10y (rightmost term)

    reason: negative times negative is positive

    ReplyDelete
  3. The second line, the "-10y" should be "+10y"

    ReplyDelete
  4. The first line should be +10 and not -10

    ReplyDelete
  5. Line 2 : -5 x -2y = 10y
    The answer should not be negative.

    ReplyDelete
  6. 2x(3x-y) - 5(3x-2y)
    = 6x^2 - 2xy - 15x + 10y

    This should be the correct equation.

    ReplyDelete
  7. At the second line, it should be +10y and not -10y

    ReplyDelete
  8. 2nd row: -10y should be +10y as - X - = +
    3rd row: x^2 and x is different
    4th row: 9x should be -9x and -2y-10y should be = -12y

    ReplyDelete
  9. The minus sign in (3x-2y) should switch to an addition sign in the second line.

    ReplyDelete
  10. The -10y from the second line should be positive

    ReplyDelete
  11. The line: 15x - 10y, should be 15x + 10y as negative 5 times negative 2y should be positive 10y.

    ReplyDelete
  12. For the second line, instead of -10y it should be +10y as negative x negative = positive.

    ReplyDelete
  13. in the 3rd row, the -10y should be +10y

    ReplyDelete
  14. One of the Mathematical Symbols in the second line is wrong.

    The answer should be:
    2x(3x-y)-5(3x-2y)
    =6xx-2xy-15x+10y
    =6x-2y-15x+10y

    ReplyDelete
  15. The answer should be:
    At line 2: should be +10y not - 10y
    At the end it should be +8y

    ReplyDelete